PDF Homework #2. Solutions. Chapter 22. The Electric Field II ~ Lifestyle HUB

An electric field is induced both inside and outside the solenoid. Strategy Using the formula for the magnetic field inside an infinite solenoid and Faraday's law, we calculate the induced emf. Since we have cylindrical symmetry, the electric field integral reduces to the electric field times the circumference of the integration path(b) Find the electric field just outside the A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 14.0 cm, giving it a charge of -39.0 μ C Part A Find the electric field just inside the paint layer. Express your answer with the appropriate units. Enter positive value if the field isA charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 19.0{\\rm cm} , giving it a charge of -13.0\\mu {\\rm C} Find the electric field just outside the paint layer. Find the electric field 8.50{\\rm cm} outside the surface of the paint layer.In it, oil drops were suspended against the gravitational force by a vertical electric field. (See Figure 9.) Given the oil drop to be 1.00 μm in radius and have a density of 920 kg/m 3: (a) Find the weight of the drop. (b) If the drop has a single excess electron, find the electric field strength needed to balance its weight.Find the electric field (a) just inside the paint later; (b) just outside the paint later; (c) 5.00 cm outside the surface of the paint layer. 4. A small sphere with a mass of 4.00 (10-6) kg and carrying a charge of 5.00 (10 8) C hangs from a thread near a very large, charged insulating sheet, as shown in the figure. The charge density on

Exercise 229 Description A charged paint is spread in a

A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 10.5 cm, giving it a charge of -22.3 µC. (a) Find the magnitude of the electric field just inside the paint layer. (b) Find the magnitude of the electric field just outside the paint layer.528 CHAPTER 17 Electric Charge and Electric Field An ion is an atom that has lost or gained one or more electrons. If one or more electrons are removed, the remaining positively charged structure is called a positive ion (Figure 17.3b). A negative ion is an atom that has gained one or more electrons (Figure 17.3c). This gaining or losing of electrons is called ionization.surface. Find the electric field both inside and outside the shell. Solution: Step 1: The charge distribution is spherically symmetric. Step 2: Since +Q is uniformly distributed on the shell, the electric field must be radially symmetric and directed outward. The magnitude of the electric field is constant on spherical surfaces of radius r. E GA Find the electric field just inside the paint layer. Express your answer with the appropriate units. Enter positive value if the field is directed radially inward and negative value if the field is directed radially outward. B Find the electric field just outside the paint layer.

A charged paint is spread in a very thin uniform layer

A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter $12.0 \mathrm{cm},$ giving it a charge of $-35.0 \mu \mathrm{C} .$ Find the electric field (a) just inside the paint layer; (b) just outside the paint layer; (c) 5.00 $\mathrm{cm}$ outside the surface of the paint layer.of diameter 10.0 cm giving it a charge of -10.0. a) find the electric field just outside the layer b) find the electric field 7.5 cm outside the surface of the layerFavorite Answer A) Exactly -- flux = E*A = Q / εo But the "enclosed charge" Q "just under the paint layer" is 0, so the field E = 0 N/C (everywhere inside the paint layer).A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 12.0 cm, giving it a charge of -15.0 microC. find the electric field: a) just inside the paint layer, b) just outside the paint layer and. c) 5.00cm outside the surface of the paint layer.Part A Constants Find the electric field just inside the paint layer. A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 12.0 cm , giving it a charge of-11. μC N/C Submit Request Answer Part B Find the electric field just outside the paint layer.

A charged paint is spread in an overly thin uniform layer over the floor of a plastic sphere of diameter 15.Zero cm , giving it a fee of -20.Zero μC .

Part A

Find the electric field just inside the paint layer.

Part B

Find the electric field just out of doors the paint layer.

Part C

Find the electric field 6.50 cm outdoor the floor of the paint layer.

EA=Q/Eo= 0 <<<<<<<<

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Q= -20.Zero μC

EA=Q/Eo

E x 4pi(0.075^2)=(20.0x10^-6)/(8.854x10^-12)

E=3.196x10^7 <<<<<<<<<<