2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH. Find an answer to your question ✅ "Which element is reduced in this reaction? 2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH" in Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use...2KMnO4 + 3Na2 SO3 + H2 O → 2MnO2 + 3Na2 SO4 + 2KOH Reducing agent in the above reaction shown is : A. K+. B. MnO4−. C. SO32−. D. Answer. Reducing agent in the above reaction shown is SO32− ion as S atom itself is oxidized. The oxidation number of S increases from +4 (in SO32− ) to...2KMnO4 + 5Na2SO3 + 3H2SO4(разб.) = 2KMnO4 + Na2SO3 + 2NaOH = 2Na2MnO4 + K2SO4 + H2O.2 KMnO4 + 3 Na2SO3 + H2O → 2 MnO2 + 3 Na2SO4 + 2 KOH. by stating "S" is the reducing agent, you avoid all that stuff.. but in this case since your instructor stated.. "enter the formula".. I'm guessing he or she is of the "the entire compound not just the S" clan.KMnO4 is an oxidizing agent, Na2SO3 is a reducing agent. Reactants: KMnO4 - Potassium manganate(VII). Search by reactants (KMnO4, Na2SO3, H2O) and by products (MnO2, Na2SO4, KOH).
2KMnO 4 + 3Na 2 SO 3 + H 2 O 2MnO 2 + 3Na 2 SO... | Toppr Ask
2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH Enter The Chemical Symbol Of The Element. Which Element Is Oxidized In This Reaction? ZnO+C→Zn+CO.Na2SO3 + KMnO4 ---> K2SO3 + NaMnO4 All solutions are aqeous. It's a simple double replacement reaction. Its a Redox Equation not a double replacement KMnO4 is a common oxidizing agent im not sure about the answer but i guess it has to change KMnO4 into MnO.100 ОВР, котрые помогут учащимся при сдаче ЕГЭ по химии.1) 2KMnO4 + 3MnSO4 + 2H2O = 5MnO2 + K2SO4 + 2H2SO42) 2KMnO4 + 16HCl = 2MnCl2 + 5Cl2 + 8H2O + 2KCl3) 5NaNO2 + 2KMnO4 + 3H2SO4 = 2MnSO4 + 5NaNO3 + K2SO4 + 3H2O4) 10FeSO4 + 2KMnO4 + 8H2SO4...Hi O₂ = H₂O + O2 =A 2n + H2SO4 = 2n SO4+H2 =. Anterior. Siguiente.
Взаимодействие перманганата калия с сульфитом натрия в трёх...
3Na2SO3 + 2KMnO4 + H2O → 3Na2SO4 + 2MnO2 + 2KOH. [ Check the balance ]. Sodium sulfite react with potassium permanganate and water to produce sodium sulfate, manganese(IV) oxide and potassium hydroxide. Find another reaction. Our channel. Подписаться.2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH. Brainly User Brainly User. 2KMnO4 is reduced in this reaction to 2MnO2. thank you.Which element is reduced in this reaction? 2KMnO4 + 3Na2SO3 + H2O → 2MnO2 + 3Na2SO4 + 2KOH. A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment.3Na2SO3 + 2KMnO4 + H2O → 3Na2SO4 + 2MnO2 + 2KOH. Reaction Information. сульфит натрия + перманганат калия + вода = сульфат натрия + оксид марганца(IV) + гидроксид калия.Ii) KMnO4 + Na2 S03 → MnO2 + Na2SO4 + KOH solve this using oxidation number method please fast. Answer: KMno4 oxidize. Explanation: it loss proto to reduce oH ion.
you have to depart an area every now and then. Else YA will "..." your textual content as you'll see above
this
2 KMnO4 + 3 Na2SO3 + H2O → 2 MnO2 + 3 Na2SO4 + 2 KOH
no longer this
2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH
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anyway..
.. "reduction".. reasonably literally approach "reduction in oxidation state"
.. "oxidation".. approach the opposite.. "increase in oxidation state"
and
.. "agents" are opposites
taking a look on the balanced equation.
.. all K, O, H and Na remained unchanged in oxidation states.. (you check this!)
and
.. Mn went from +7 in KMnO4 to +4 in MnO4
.. S went form +4 in Na2SO3 to +6 in Na2SO4
since
.. Mn went from +7 to +4.... Mn used to be REDUCED and is the OXIDIZING AGENT
.. S went from +4 to +6.. . ...S used to be OXIDIZED and is the REDUCING AGENT
**********
now..
.. SOME instructors would say "S" is the decreasing agent
.. SOME instructors would say "Na2SO3" is the lowering agent
I might most definitely say "S".. the keep away from the arguments
. (1) Na2SO3 is an ionic forged.. it's actually the SO3(2-) what used to be oxidized
. (2) is it the Na2SO3 or the Na2SO4 that was once "oxidized".. reactant or product
..... .or is it the SO3(-2) or SO4(-2) that is the "reducing agent"?
by pointing out "S" is the lowering agent, you steer clear of all that stuff.. but in this case since your instructor said.. "enter the formula".. I'm guessing he or she is of the "the entire compound not just the S" extended family.
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final solution... . Na2SO3
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